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Torque = P(cross product) E
P = q*d = (10^-6)*0.02 = 2* 10^-8
E = 10^-15
torque = PEsinx = 2 * 10^-23 * 1 (since max value of sinx is 1 )
ANSWER = 2 * 10^ -23
torque=p.Esin(theta)
here,
p=q*distance b/w them
E=10raise to power -15
sin(theta) has to be maximum as torque should be max. it implies theta=90
now,
p=10 raise to power 6*2*10 raise to the power -2
=10 raise to power 4.
it implies torque=10^4*10^-15
=10^-11(answer).
(please ignore my long writings:-})
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