an electric dipole consists of two oppsite charges of magnitude 1uc separted by distance of 2cm the dipole is placed in an electric field 10to power -15 vm-1the max torque does the field exert on the dipole

Question

Husna Begum · Answer

Torque = P(cross product) E P = q*d = (10^-6)*0.02 = 2* 10^-8 E = 10^-15 torque = PEsinx = 2 * 10^-23 * 1 (since max value of sinx is 1 ) ANSWER = 2 * 10^ -23

ashish badoni · Answer

torque=p.Esin(theta)

here,

p=q*distance b/w them

E=10raise to power -15

sin(theta) has to be maximum as torque should be max. it implies theta=90

now,

p=10 raise to power 6*2*10 raise to the power -2

=10 raise to power 4.

it implies torque=10^4*10^-15

=10^-11(answer).

(please ignore my long writings:-})

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an electric dipole consists of two oppsite charges of magnitude 1uc separted by distance of 2cm the dipole is placed in an electric field 10to power -15 vm-1the max torque does the field exert on the dipole

an electric dipole consists of two oppsite charges of magnitude 1uc separted by distance of 2cm the dipole is placed in an electric field 10to power -15 vm-1the max torque does the field exert on the dipole

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