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an electric dipole consists of two oppsite charges of magnitude 1uc separted by distance of 2cm the dipole is placed in an electric field 10to power -15 vm-1the max torque does the field exert on the dipole
Torque = P(cross product) E P = q*d = (10^-6)*0.02 = 2* 10^-8 E = 10^-15 torque = PEsinx = 2 * 10^-23 * 1 (since max value of sinx is 1 ) ANSWER = 2 * 10^ -23
Torque = P(cross product) E
P = q*d = (10^-6)*0.02 = 2* 10^-8
E = 10^-15
torque = PEsinx = 2 * 10^-23 * 1 (since max value of sinx is 1 )
ANSWER = 2 * 10^ -23
torque=p.Esin(theta) here, p=q*distance b/w them E=10raise to power -15 sin(theta) has to be maximum as torque should be max. it implies theta=90 now, p=10 raise to power 6*2*10 raise to the power -2 =10 raise to power 4. it implies torque=10^4*10^-15 =10^-11(answer). (please ignore my long writings:-})
torque=p.Esin(theta)
here,
p=q*distance b/w them
E=10raise to power -15
sin(theta) has to be maximum as torque should be max. it implies theta=90
now,
p=10 raise to power 6*2*10 raise to the power -2
=10 raise to power 4.
it implies torque=10^4*10^-15
=10^-11(answer).
(please ignore my long writings:-})
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