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Q1) A capacitor of capacitance c1=1 uF CHARGED to a voltage v=110 volt is connected in parallel to terminals of a circuit consisting of 2 ncharged charges capacitors connected in series and possessing the capacitance c2=2 uF . what charge will flow through the connectiong wires?

Shyam Chand , 12 Years ago
Grade 12th Pass
anser 1 Answers
Ajaykrishnan Jayagopal

Last Activity: 10 Years ago

“... consisting of 2 ncharged charges capacitors ….”  is being interpreted as “ consisting of 2 uncharged capacitors”
Intial potential difference across 1uF capacitor C1 is Vo = 110 V.
When the circuit element consisting  of two capacitors of capacitance C2 = 2 uF , is connected in parallel with C1, charge starts flowing through the connecting wires because of the potential difference between the connected capacitor plates.
The charge finally stops flowing when the potential difference across all the capacitors become equal.
Let V be the final voltage across each of the capacitors.
                q = CV
By  Law of conservation of charge, 
   total initial charge = total final charge
   C1 x Vo = C1 x V + C2 x V + C2 x V
   1 uF x 110 V = (1 + 2 + 2) uF x V
   V = 22 volts
 Now, initial charge on the 2 uF capacitor is zero and the final charge Q = 2 uF x 22 V = 44 uC
Therefore, the charge that flows through the connecting wires = Q =  44 uC

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