Ajaykrishnan Jayagopal
Last Activity: 10 Years ago
“... consisting of 2 ncharged charges capacitors ….” is being interpreted as “ consisting of 2 uncharged capacitors”
Intial potential difference across 1uF capacitor C1 is Vo = 110 V.
When the circuit element consisting of two capacitors of capacitance C2 = 2 uF , is connected in parallel with C1, charge starts flowing through the connecting wires because of the potential difference between the connected capacitor plates.
The charge finally stops flowing when the potential difference across all the capacitors become equal.
Let V be the final voltage across each of the capacitors.
q = CV
By Law of conservation of charge,
total initial charge = total final charge
C1 x Vo = C1 x V + C2 x V + C2 x V
1 uF x 110 V = (1 + 2 + 2) uF x V
V = 22 volts
Now, initial charge on the 2 uF capacitor is zero and the final charge Q = 2 uF x 22 V = 44 uC
Therefore, the charge that flows through the connecting wires = Q = 44 uC
