Q1) A capacitor of capacitance c1=1 uF CHARGED to a voltage v=110 volt is connected in parallel to terminals of a circuit consisting of 2 ncharged charges capacitors connected in series and possessing the capacitance c2=2 uF . what charge will flow through the connectiong wires?

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Ajaykrishnan Jayagopal · Answer

“... consisting of 2 ncharged charges capacitors ….” is being interpreted as “ consisting of 2 uncharged capacitors” Intial potential difference across 1uF capacitor C1 is V o = 110 V. When the circuit element consisting of two capacitors of capacitance C2 = 2 uF , is connected in parallel with C1, charge starts flowing through the connecting wires because of the potential difference between the connected capacitor plates. The charge finally stops flowing when the potential difference across all the capacitors become equal. Let V be the final voltage across each of the capacitors. q = CV By Law of conservation of charge , total initial charge = total final charge C1 x V o = C1 x V + C2 x V + C2 x V 1 uF x 110 V = (1 + 2 + 2) uF x V V = 22 volts Now, initial charge on the 2 uF capacitor is zero and the final charge Q = 2 uF x 22 V = 44 uC Therefore, the charge that flows through the connecting wires = Q = 44 uC

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Q1) A capacitor of capacitance c1=1 uF CHARGED to a voltage v=110 volt is connected in parallel to terminals of a circuit consisting of 2 ncharged charges capacitors connected in series and possessing the capacitance c2=2 uF . what charge will flow through the connectiong wires?

Q1) A capacitor of capacitance c1=1 uF CHARGED to a voltage v=110 volt is connected in parallel to terminals of a circuit consisting of 2 ncharged charges capacitors connected in series and possessing the capacitance c2=2 uF . what charge will flow through the connectiong wires?

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