Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Q1) A capacitor of capacitance c1=1 uF CHARGED to a voltage v=110 volt is connected in parallel to terminals of a circuit consisting of 2 ncharged charges capacitors connected in series and possessing the capacitance c2=2 uF . what charge will flow through the connectiong wires?
“... consisting of 2 ncharged charges capacitors ….” is being interpreted as “ consisting of 2 uncharged capacitors”Intial potential difference across 1uF capacitor C1 is Vo = 110 V.When the circuit element consisting of two capacitors of capacitance C2 = 2 uF , is connected in parallel with C1, charge starts flowing through the connecting wires because of the potential difference between the connected capacitor plates.The charge finally stops flowing when the potential difference across all the capacitors become equal.Let V be the final voltage across each of the capacitors. q = CVBy Law of conservation of charge, total initial charge = total final charge C1 x Vo = C1 x V + C2 x V + C2 x V 1 uF x 110 V = (1 + 2 + 2) uF x V V = 22 volts Now, initial charge on the 2 uF capacitor is zero and the final charge Q = 2 uF x 22 V = 44 uCTherefore, the charge that flows through the connecting wires = Q = 44 uC
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -