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An electron is revolving around a line charge having linear density of charge 1 micro coulomb. If the radius of the path is 1 cm, then what ll b the velocity of the elctron????

8 years ago

Answers : (2)

Ashish Gupta
IIT Roorkee
askIITians Faculty
12 Points
							\text{ Force = 2\lambda Ke/r = mv^{2}/r => v = root [2 X 10^{-6} X 9 X 10^{9} X 1.6 X 10^{-19}]/[9.1 X 10^{-31}] = 10^{8} m/s }
6 years ago
Atal Tiwari
37 Points
Since, the charge density of line is 1micro coulomb,
i.e. it can be written as 10-6 C.
and radius=1cm
Now, Electric Field E= ∂/2-pi-epsilon naught-r
where, ∂ is linear charge density and r is the radius.
then by,
Er= ∂/2-pi-epsilon naught                               
V= ∂/2-pi-epsilon naught
V= 4.5 x 109 x 10-6
    = 4.5 X 103 J/C
As we know k=qV
1/2 mv2= 1.6 x 10-19 x 4.5 x 10
v=4x107 m/s
5 years ago
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