MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        A drop of liquid of diametre 2.8mm breaks up inti 125 identical drops The change in energy is nearly
10 years ago

Answers : (2)

askiitiansexpert soumyajit_iitkanpur
8 Points
							
						
10 years ago
askiitiansexpert soumyajit_iitkanpur
8 Points
							

let the radius of each droplet be r m

Volume of bigger drop = total volume of 125 droplets

(4/3)* pi * (1.4*10-3)3 = 125 * (4/3) * pi * r3

=> r = (1.4/5)* 10-3 = 0.28*10-3

change in surface area = ds = 4*pi* [125* (0.28*10-3) 2 - (1.4*10-3)2] m

                                       = 0.0984 m

if surface tension of the liquid ne T Nm-1 then work done W = Tds = 0.098T J.

10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details