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Grade: 12

                        

Two insulating small spheres are rubbed against each other and placed 1cm apart.If they attract each other with a force of 0.1 N how many electrons weretransfered from 1 sphere to the otherduring rubbing

11 years ago

Answers : (4)

askiitian.expert- chandra sekhar
10 Points
							

Hi Pallavi,

F= 0.1 N = 9 * 109 * q2/r2

q2= 0.1 * 0.012/(9 * 109)

q2= 10/9 * 10-15

no of electrons transferred = q/1.6 * 10-19= 3.3333*10-16/1.6 * 10-19

                                                             =2.08 *103

11 years ago
s maheshwara srinivas
22 Points
							
2*1011 electrons
6 years ago
Anjali Singh
26 Points
							
 

F= 0.1 N = 9 * 109 * q2/r2

 

q2= 0.1 * 0.012/(9 * 109)

 

q2= 10/9 * 10-15

 

q= 3.34* 10-8
 

no of electrons transferred = q/1.6 * 10-19= 3.34* 10-8/1.6 * 10-19

 

                                                             =2 *1011 (Approx.)

5 years ago
Krish Gupta
askIITians Faculty
81 Points
							 

Hi Pallavi,

F= 0.1 N = 9 * 109 * q2/r2

q2= 0.1 * 0.012/(9 * 109)

q2= 10/9 * 10-15

 

F= 0.1 N = 9 * 109 * q2/r2

 

q2= 0.1 * 0.012/(9 * 109)

 

q2= 10/9 * 10-15

 

q= 3.34* 10-8
 

no of electrons transferred = q/1.6 * 10-193.34* 10-8/1.6 * 10-19

 

                                                             =2 *1011 (Approx.)

Helps !

 

6 months ago
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