Two insulating small spheres are rubbed against each other and placed 1cm apart.If they attract each other with a force of 0.1 N how many electrons weretransfered from 1 sphere to the otherduring rubbing
pallavi pradeep bhardwaj , 15 Years ago
Grade 12
4 Answers
askiitian.expert- chandra sekhar
Last Activity: 15 Years ago
Hi Pallavi,
F= 0.1 N = 9 * 109 * q2/r2
q2= 0.1 * 0.012/(9 * 109)
q2= 10/9 * 10-15
no of electrons transferred = q/1.6 * 10-19= 3.3333*10-16/1.6 * 10-19
=2.08 *103
s maheshwara srinivas
Last Activity: 10 Years ago
2*1011 electrons
Anjali Singh
Last Activity: 9 Years ago
F= 0.1 N = 9 * 109 * q2/r2
q2= 0.1 * 0.012/(9 * 109)
q2= 10/9 * 10-15
q= 3.34* 10-8
no of electrons transferred = q/1.6 * 10-19= 3.34* 10-8/1.6 * 10-19
=2 *1011 (Approx.)
Krish Gupta
Last Activity: 4 Years ago
Hi Pallavi,
F= 0.1 N = 9 * 109 * q2/r2
q2= 0.1 * 0.012/(9 * 109)
q2= 10/9 * 10-15
F= 0.1 N = 9 * 109 * q2/r2
q2= 0.1 * 0.012/(9 * 109)
q2= 10/9 * 10-15
q= 3.34* 10-8
no of electrons transferred = q/1.6 * 10-19= 3.34* 10-8/1.6 * 10-19
=2 *1011 (Approx.)
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