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supposen the second charge in the previous problem is -1*10^-6c.Locate the position where a third charge will not expierience a net force.
Hi Pallavi, As one charge is + and other is -ve definitely the third charge should be negative as the negative charge has less magnitude compared to + ve charge. third charge should be on the the line joining the two charges. it should be away from + ve and closeer to - ve. it sholud not be in between the two. then let third charge be x distance from -ve charge then it will be at 10+x from + charge. |F1|=|F2| 2*q/(10+x)2=1*q/(x)2 2x2=100+x2+20x x2-20x-100=0 x=10±10√2 = 10+10√2
Hi Pallavi,
As one charge is + and other is -ve definitely the third charge should be negative as the negative charge has less magnitude compared to + ve charge.
third charge should be on the the line joining the two charges.
it should be away from + ve and closeer to - ve.
it sholud not be in between the two.
then let third charge be x distance from -ve charge then it will be at 10+x from + charge.
|F1|=|F2|
2*q/(10+x)2=1*q/(x)2
2x2=100+x2+20x
x2-20x-100=0
x=10±10√2 = 10+10√2
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