Plzzzz someone explain me how to plot the graphs for two particle charges for the variation of electric field v/s x or y coordiante. Plzzz explain carefully with certain examples.

Electric field v/s x &y coordinates;

Potential v/s x &y coordinates

For eg, if two identical positive point charges q are placed on the axis at x=-a and x = +a. Then how can we plot the variation of electric field v/s x & y ccoordinates

Question

Plzzzz someone explain me how to plot the graphs for two particle charges for the variation of electric field v/s x or y coordiante. Plzzz explain carefully with certain examples.

Electric field v/s x &y coordinates;

Potential v/s x &y coordinates

For eg, if two identical positive point charges q are placed on the axis at x=-a and x = +a. Then how can we plot the variation of electric field v/s x & y ccoordinates

pratham ashish · Answer

hi,

it's very easy just notice that E is vector but V is scalar.

just mark q at both -a & +a , u'll will see (mathematically/physically) that ,at the points nearer to RHS of -a the distance tends to zero hence E tends to ∞( it 's +∞ bcz distace from -a will b + if we r on RHS of a point)

at the mid (at 0) E wud b zero as E of both cancels each other

and LHS of +a it wud -∞(near to +a chrge at this pt wud dominate over the othr as r tends to zero E due to tis charge wud tends to ∞ & distance from this pt to any point on LHS wud b - )

similarly on LHS of -a

r(distace) is -ve &just on LHS of -a E wud tends to-∞ as r tends to 0 & E wud tend to 0 at x= -∞

onRHS of +a

first E ->+∞ just on RHS & on going further it wud decrease & -> 0 at x= +∞

the graph wud b continuous LHS of -a, b/w -a &a and RHS of a

it wud b discont. at -a &a only .

so will b the V graph vs x (u can use the relation dV/Dx= -E(x) )

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