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A rod AB of mass M and length L is positively charged with liner charge density 1 col/m.It is suspended at end A and is hanging freely.If a horizontal electric field E is switched on,find the angular acceleration

A rod AB of mass M and length L is positively charged with liner charge density 1 col/m.It is suspended at end A and is hanging freely.If a horizontal electric field E is switched on,find the angular acceleration

Grade:12

1 Answers

Chetan Mandayam Nayakar
312 Points
9 years ago

moment of inertia =I =ML2/3, assume that the linear charge density is constant. Torque=(L/2)(kLE),k is linear charge density.

Torque=I*(alpha), where 'alpha' is angular acceleration.After simplifying we get α=(3kE/2M)

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