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Two small spheres having same mass and charge are loacated at the same vertical line at heights h 1 and h 2 (h 2 >h 1 ). They both are thrown simultaneously with the same velocity V in the same direction along the horizontal. From the initial vertical line, the first sphere hits the ground ata distance l. Then at this instance height of second ball,H=?? Ans in terms of h 1 ,h 2 ,l,V and g(acc due to gravity)
let mass of both the charges is m and charge on both the charges is q take a sphere which is at height h1 two forces act on it force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence h1=1/2(g+qe/m)t^2 let t is time taken by small sphere in travelling distance l=vt , t=l/v let x is distance travelled by second sphere forces acting on it force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m) X=1/2(g-qe/m)t^2 height at this instant is h2-x x=gl^2/v^2-h1 hence height is h2-(gl^2/v^2)
let mass of both the charges is m and charge on both the charges is q
take a sphere which is at height h1 two forces act on it
force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence
h1=1/2(g+qe/m)t^2
let t is time taken by small sphere in travelling distance
l=vt , t=l/v
let x is distance travelled by second sphere
forces acting on it
force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)
X=1/2(g-qe/m)t^2
height at this instant is h2-x
x=gl^2/v^2-h1
hence height is h2-(gl^2/v^2)
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