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Electrostatics

An infinitely large surface of uniform charge density ? has a disc of radius R cut out . The magnitude of the electric field at a distance a above the centre of the disc is ???

Profile image of narsim kannan
15 Years agoGrade
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1 Answer

Profile image of Chetan Mandayam Nayakar
15 Years ago

when the disc is not cut out, electric field=(charge density)/k, from this, subtract the electric field of a dic of radius R at a distance a above the centre of the disc. this is the solution