An infinitely large surface of uniform charge density ? has a disc of radius R cut out . The magnitude of the electric field at a distance a above the centre of the disc is ???
narsim kannan , 13 Years ago
Grade
1 Answers
Chetan Mandayam Nayakar
Last Activity: 13 Years ago
when the disc is not cut out, electric field=(charge density)/k, from this, subtract the electric field of a dic of radius R at a distance a above the centre of the disc. this is the solution
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