Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Three identical small balls, each of mass 0.1g, are suspended at one point on silk thread having a length of l=20cm. What charges should be imparted to the balls for each thread to form an angle of 30 degree with the verticle.

Three identical small balls, each of mass 0.1g, are suspended at one point on silk thread having a length of l=20cm. What charges should be imparted to the balls for each thread to form an angle of 30 degree with the verticle.

Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Its a  simple problem just put the values in the formula....

Mohd Ehteshaam
11 Points
3 years ago
0.05x1.732x2 =a a=0.1732 meter now let the charge be q force between any two balls = kq^2 / r^2 (9x10^9)q^2/ (0.1732)^2 F=3x(10)^11(q^2) Newton now to balls will apply this force at 60* angle so vector sum of these force 2Fcos 30 (1.732x 3x(10)^11)q^2 = 5.2x(10)^11(q^2) now this force must balance component of tension in string in horizontal direction so mg tan 30* = 5.2x(10)^11(q^2) puttinng the values we get q= 0.1/3 micro coulomb or 0.03x(10)^-6

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free