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Grade: 12
        

The electric flux over a sphere of radius 1m is  A . If radius of the sphere were doubled without changing the charge enclosed electric flux would become ?



 


7 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
							

Dear javed

For a volume V with surface S, Gauss's law states that

\Phi_{E,S} = \frac{Q}{\varepsilon_0}

where ΦE,S is the electric flux through S, Q is total charge inside V, and ε0 is the electric constant

since Q=constant flux will remain same equal to A

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

 

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7 years ago
vikas askiitian expert
509 Points
							

flux is independent of area of sphere & it depends only on charge enclosed by the surface so

the sphere whose radius is double will have same flux A...

7 years ago
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