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let the mid point of base is p..
distance of q charge from P is (42 -12)1/2 =sqrt15cm.... (by using pythogorus theorem)
=sqrt15x10-2m
potential due to q charge is Vq= kq/r
= 100kq/sqrt15 ...........1
distance of any -q charge from p is 1cm
potential due to two -q charges at p will be
2V-q = -2x100kq
=-200kq .........2
net potential is addition of these
VT = -200kq + 100kq/sqrt15
=1.09x107 V
=
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