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1701_24975_Electric potential.gif

Grade:Upto college level

1 Answers

vikas askiitian expert
509 Points
11 years ago

let the mid point of base is p..

distance of q charge from P is (42 -12)1/2 =sqrt15cm....           (by using pythogorus theorem)

                                                             =sqrt15x10-2m

potential due to q charge is Vq= kq/r

                                           = 100kq/sqrt15 ...........1

distance of any -q charge from p is 1cm

potential due to two -q charges at p will be

           2V-q = -2x100kq

                  =-200kq     .........2

net potential is addition of these

        VT =  -200kq + 100kq/sqrt15

            =1.09x107 V

            =

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