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A charge Q is spread non uniformly on the surface of hollow sphere of radius R such that charge density is given by σ=σ 0 (1-sin θ) , where θ is the usual polar angle. The potential at the centre of sphere is (a) Q/4Πε 0 R (b) Q/Πε 0 R (c) Q/8Πε 0 R (d) Q/2Πε 0 R


A charge Q is spread non uniformly on the surface of hollow sphere of radius R such that charge density is given by σ=σ0(1-sinθ), where θ is the usual polar angle. The potential at the centre of sphere is


(a) Q/4Πε0R (b) Q/Πε0R (c) Q/8Πε0R (d) Q/2Πε0R

Grade:12

1 Answers

Jeetendra Singh Chauhan
18 Points
10 years ago

its C because At 90' charge density is Zero And At 0' its Maximum therefore we can cut the hollow  sphere in equal two parts & Then we get the "C" option.

if the answer & approach Is wrong then you must tell me what the correct approach to attempt this quetion as you find answer 

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