A charge Q is spread non uniformly on the surface of hollow sphere of radius R such that charge density is given by σ=σ₀(1-sinθ), where θ is the usual polar angle. The potential at the centre of sphere is

(a) Q/4Πε₀R (b) Q/Πε₀R (c) Q/8Πε₀R (d) Q/2Πε₀R

its C because At 90' charge density is Zero And At 0' its Maximum therefore we can cut the hollow  sphere in equal two parts & Then we get the "C" option.

if the answer & approach Is wrong then you must tell me what the correct approach to attempt this quetion as you find answer