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# two identical charges having the charge 2*10^(-4) C,and having the mass 10g are kept at separation by 10cm.what would be the velocity of particles when they the separation is maximum.

509 Points
10 years ago

initial potential energy is (PE)i = kq2 /r                  (charges are of same magnitude q)

k = 9 . 109 units

(PE)i  =3600j                 (after substituting value of charge and K)

finally when distance is maximum then (PE)=kq2 /r

r=r(max)=infinity

so final potential energy is 0...

initially kinetic energy is zero ....

finally kinetic energy is (KE)f =  mv12 /2   +  mv2 2 /2

=m(v12 + v22 )/2 ................1

from conservation of energy ,total energy initial = total energy final

therefore ,     m(v12 +v22 )/2 =3600 ..................2

since no external; force is acting so momentam will be conserved..

initial momentam =0

final momentam=mv1 +mv2

mv1 +mv2 =0

v1=-v2 ..................1

now from eq 2 putting v1=-v2

v1=600m/s

v2=-600m/s