Click to Chat
1800-2000-838
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
a thin conducting ring of radius R has linear charge density ?=?'cosa where ?'is a constant and a is the azimuthal angle. find the magnitude of the electric field strenght at the centre of the ring
hi sneha, after an angle a cut an element of length rda,so charge dq=?'cosa*rda elec field due to this elemet ,dE=kdq/r2 now consider another element of length rda at an angle -a,the magnitude dE due to both these elements is same and therefore total elec field=2dE cosa in -x direction,sina components in +y dir.wll cancel out so ,elec field at centre,E can be found by integrating this expression fron a=0 to pi and the elec field will be in -x direction.
hi sneha,
after an angle a cut an element of length rda,so charge dq=?'cosa*rda
elec field due to this elemet ,dE=kdq/r2
now consider another element of length rda at an angle -a,the magnitude dE due to both these elements is same
and therefore total elec field=2dE cosa in -x direction,sina components in +y dir.wll cancel out
so ,elec field at centre,E can be found by integrating this expression fron a=0 to pi and the elec field will be in -x direction.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -