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Grade: 12
        a thin conducting ring of radius R has linear charge density  ?=?'cosa  where  ?'is a constant and  a is the azimuthal angle. find the magnitude of the electric field strenght at the centre of the ring    
10 years ago

Answers : (1)

askiitian expert akshay singh
8 Points
							

hi sneha,

 after an angle a cut an element of length rda,so charge dq=?'cosa*rda

elec field due to this elemet ,dE=kdq/r

now consider another element of length rda at an angle -a,the magnitude dE due to both these elements is same

and therefore total elec field=2dE cosa in -x direction,sina components in +y dir.wll cancel out

 

so ,elec field at centre,E can be found by integrating this expression fron a=0 to pi and the elec field will be in -x direction.

10 years ago
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