a thin half ring of radius R=20cm is uniformly charged with a total charge q=0.70mC.find the magnitude of electric field strength at the centre of curvature of this half ring

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askiitian expert akshay singh · Answer

hi sneha, charge per unit length, &lambda;=total charge/half the circumference after an angle @ cut an element of length rd@, therefore,charge dq= &lambda;rd@ now elec field due to this element is dE=kdq/r 2 the cos @ component of dE will be cancelled and sin @ component will add up therefore total elec field=2dEsin @ this expression can be integrated from @=0 to pi/2 to get the desired answer

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a thin half ring of radius R=20cm is uniformly charged with a total charge q=0.70mC.find the magnitude of electric field strength at the centre of curvature of this half ring

a thin half ring of radius R=20cm is uniformly charged with a total charge q=0.70mC.find the magnitude of electric field strength at the centre of curvature of this half ring

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