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a thin half ring of radius R=20cm is uniformly charged with a total charge q=0.70mC.find the magnitude of electric field strength at the centre of curvature of this half ring
hi sneha, charge per unit length, λ=total charge/half the circumference after an angle @ cut an element of length rd@, therefore,charge dq= λrd@ now elec field due to this element is dE=kdq/r2 the cos @ component of dE will be cancelled and sin @ component will add up therefore total elec field=2dEsin @ this expression can be integrated from @=0 to pi/2 to get the desired answer
hi sneha,
charge per unit length, λ=total charge/half the circumference
after an angle @ cut an element of length rd@,
therefore,charge dq= λrd@
now elec field due to this element is dE=kdq/r2
the cos @ component of dE will be cancelled and sin @ component will add up
therefore total elec field=2dEsin @
this expression can be integrated from @=0 to pi/2 to get the desired answer
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