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What is the answer of this question ?please explain step by step

Suraj Kumar , 5 Years ago
Grade
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Solution of equation z(z-3i) = 2(2+3i) :
z^2 – 3zi = 4 + 6i 
z^2 – (3z)i -4-6i =0 
Apply quadratic equation formula 
z = 3i (+ or – ) sqrt(7+24i) / 2 
Hope this will help 
Good luck 
 

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