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This is the question from D.C Pandey.Sir ,plz give me solution of this question quickly

Kaushki , 7 Years ago

Grade 12th pass

1 Answers

Eshan

Last Activity: 7 Years ago

Dear student,

Since spring compresses by 1m on application of 100N, the spring constant of force is $k=100N/m$ .

During compression, the block loses its kinetic and gravitational potential energy into elastic potential energy.

Hence $\dfrac{1}{2}mv^2+mgxsin30^{\circ}=\dfrac{1}{2}kx^2$

Here, $x=2m$

Therefore, $v=\sqrt{20}m/s$

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