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solve the equation Cosa+sin2a+cos3a=0
(cosa+cos3a)+sin2a=02cos2a.cosa+2sinacosa=02cosa(cos2a+sina)=0=> cosa=0 or cos2a+sina=0=>a=pi/2 or 1-2sin^2a+sina=02sin^2a-sina-1=0sina={1+-sqrt(1-4(2)(-1))}/2(2)=>sina=1,-1/2=>a=pi/2 and 7pi/6hence a=pi/2,7pi/6Thanks & regardsRinkoo GuptaAskIITians Faculty
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