0

Guest

Courses New

Question Number 23 from electrochemistry....................... ...

Question Number 23 from electrochemistry.......................
 
... 

Question Image
Grade:12th pass

1 Answers

Sahani Kumar
99 Points
5 years ago
Option (1)  is correct.   
I have explained it below. 
 
Given:E cell = 1.10 volt.
E^o _c_e_l_l = – (0.059/2)logKc. 
 Kc is a equilibrium constant
Now on putting the value of E cell in above equation we get 
1.10= -- (0.059/2)logKc
–( 1.10 * 2)/0.059 = log Kc.    on solving we will get
– 37=logKc
So Kc=10^-37
Regards
Askiitian member 
If you like this answer please encourage us by approving this answer. 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Discuss with colleagues and IITians

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More