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Grade: 12th pass
        
Question Number 23 from electrochemistry.......................
 
... 
one year ago

Answers : (1)

Sahani Kumar
99 Points
							
Option (1)  is correct.   
I have explained it below. 
 
Given:E cell = 1.10 volt.
E^o _c_e_l_l = – (0.059/2)logKc. 
 Kc is a equilibrium constant
Now on putting the value of E cell in above equation we get 
1.10= -- (0.059/2)logKc
–( 1.10 * 2)/0.059 = log Kc.    on solving we will get
– 37=logKc
So Kc=10^-37
Regards
Askiitian member 
If you like this answer please encourage us by approving this answer. 
 
one year ago
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