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Grade 12th passDiscuss with colleagues and IITians

Question Number 23 from electrochemistry.......................

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Question image for Question Number 23 from electrochemistry.........

aayeshaa

7 Years agoGrade 12th pass

1 Answer

Sahani Kumar

Approved Tutor Answer7 Years ago

Option (1) is correct.

I have explained it below.

Given:E cell = 1.10 volt.

$E^o _c_e_l_l$ = – (0.059/2)logKc.

Kc is a equilibrium constant

Now on putting the value of E cell in above equation we get

1.10= -- (0.059/2)logKc

–( 1.10 * 2)/0.059 = log Kc. on solving we will get

– 37=logKc

So Kc=10^-37

Regards

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