Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
Maximum number of real solution does the equation x^7+ax^5+bx^3+cx-d=0(a,b,c,d>0) Maximum number of real solution does the equation x^7+ax^5+bx^3+cx-d=0(a,b,c,d>0)
Dear Suraj f’(x) = 7x^6 + 5ax^4 + 3b x^2 +c this is always postive hence this is incresing function. hence it will cut x axis only one time. hence number of real roots = 1
Dear student Here is the correct explanation f’(x) = 7x^6 + 5ax^4 + 3b x^2 +cThis is greater than zero Because a, b , c , d > 0 f'(x) > 0=> This indictes it is monotonically increasing Lim (x->-inf. ) f(x) = -infinity Lim (x->inf. ) f(x) = infinity So, it has maximum real roots = 1 Complex real roots = 7-1 =6
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -