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In a sample ,electron jumps from 5th excited state to ground state then number of spectral lines in visible range will be

Suraj Kumar , 5 Years ago
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anser 2 Answers
Arun

Last Activity: 5 Years ago

The right ans is 6
5-2(5-2+1)/2
6
 
Hope it helps
In case of qny difficulty, please feel free to ask
 
Regards
Arun

Vikas TU

Last Activity: 5 Years ago

Excited state is 5th orbit, then n = 5 + 1 = 6
Ground state, then n = 1 + 1 = 2
Number of spectral lines from 5th excited state to ground state i.e., from n = 6 to n = 2
V1 = (6-2)*(6-2+1)/2 = 10 
from n=6 to n= 3 
V2 = (6-3)*(6-3+1)/2 = 6 
No. of spectral lines = v1-v2 
= 10-6 =4 

Hope this helps 

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