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I need solution of Question Number 37 from redox reactions..... Question in the image

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Profile image of aayeshaa
7 Years agoGrade 12th pass
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2 Answers

Profile image of Arun
7 Years ago
Dear student
 
strength of H2O2 = Volume of Na2S2O3 used * Normality * 1.7 / (sample weight of H2O2 in ml)
 
= 20 * 0.1 * 1.7 / 50 = 0.068
 
Regards
Arun
Profile image of aayeshaa
7 Years ago
Sir,Why did you multiply the above equation by 1.7? Please explain it.