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Grade:

                        

For a projectile thrown up an incline plane (making an angle theta with horizontal ),maximum range on the incline can be achieved by projecting at an angle .................... From the horizontal (theta is acute).

one year ago

Answers : (2)

Arun
25285 Points
							
Dear student
 
As we know
range= u² sin 2 theta/g
Hence for maximum range sin2 theta = 1
 
Hence 2 theta = 90 degree
 
Hence theta = 45°
one year ago
Vikas TU
13783 Points
							
Dear student 
R = u^2Sin2Q /g 
Rmax = u^2 /g 
So, Sin2Q =1 
2Q = Sin^-1 (1) 
2Q = 90 degree 
Q = 45 degree 
Hope this helps 
one year ago
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