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Find p for x^2-px+p+3=0 has both root negative (P belongs to R)
Find p for x^2-px+p+3=0 has both root negative (P belongs to R)
2 Answers
Vikas TU
Dear student
Real and distinct roots
D > 0
=> (-p)^2 -4(p+3)(1) > 0
> p^2 -4p -12 >0
(p-6)(p+2)>0
p>6 or p>-2
p>6 is the ans
> p^2 -4p -12 >0
(p-6)(p+2)>0
p>6 or p>-2
p>6 is the ans
Arun
Dear student
for both roots negative
use D greater than 0
– b/2a less than 0
f(0) less than 0
hope it helps
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