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Find p for x^2-px+p+3=0 has both root negative (P belongs to R)
Dear student Real and distinct rootsD > 0=> (-p)^2 -4(p+3)(1) > 0 > p^2 -4p -12 >0 (p-6)(p+2)>0 p>6 or p>-2 p>6 is the ans
Dear student for both roots negative use D greater than 0 – b/2a less than 0 f(0) less than 0 hope it helps
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