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Find p for x^2-px+p+3=0 has both root negative (P belongs to R)

Find p for x^2-px+p+3=0 has both root negative     (P belongs to R)
 

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2 Answers

Vikas TU
14149 Points
4 years ago
Dear student 
Real and distinct roots
D > 0
=> (-p)^2 -4(p+3)(1) > 0 
> p^2 -4p -12 >0 
(p-6)(p+2)>0 
p>6 or p>-2 
p>6 is the ans 
Arun
25750 Points
4 years ago
Dear student
 
for both roots negative
 
use D greater than 0
 – b/2a less than 0
 
f(0) less than 0
 
hope it helps

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