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Grade:
        
Find p for x^2-px+p+3=0 has both root negative     (P belongs to R)
 
3 months ago

Answers : (2)

Vikas TU
9499 Points
							
Dear student 
Real and distinct roots
D > 0
=> (-p)^2 -4(p+3)(1) > 0 
> p^2 -4p -12 >0 
(p-6)(p+2)>0 
p>6 or p>-2 
p>6 is the ans 
3 months ago
Arun
23020 Points
							
Dear student
 
for both roots negative
 
use D greater than 0
 – b/2a less than 0
 
f(0) less than 0
 
hope it helps
3 months ago
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