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```
A bullet of mass 0.020kg traveling horizontally at 50m/s is stopped after moving through a distance of 0.10 in a concrete block. What is the average retarding force applied to the bullet by the concrete?

```
6 years ago

```							v2= u2+ 2as
02= 502+ 2(a)(0.1)
a = -12500m/s2
F = ma
= 0.020 x (-12500)
= -250N
The answer is 250N, not -250N. A retarding force is negative in connotation.
```
6 years ago
```							impulse=change in momentum
t=dist./speed=.1/50=.002 sec
impulse=force*time =F*t
change in momentum=0-mu=-.02*50=-1
therefore ,F=-1/.0002=5000N
```
6 years ago
```							impulse=change in momentum
t=dist./speed=.1/50=.002 sec
impulse=force*time =F*t
change in momentum=0-mu=-.02*50=-1
therefore ,F=-1/.002=500N
```
6 years ago
```							v2-u2=2as
0=2500+2a[0.1]
a= -12500
f=ma
=0.020
=-250N
```
6 years ago
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