Question icon
Grade 12Discuss with colleagues and IITians

show that the number of ways one can choose a set of distinct positive integers, each smaller than or equal to 50 ,such that their sum is odd,is 2^49

Profile image of pritam samanta
16 Years agoGrade 12
Answers icon

1 Answer

Profile image of Badiuddin askIITians.ismu Expert
16 Years ago

Dear pritam

we have 25 even number and 25 odd number

for sum to be odd ,we must select odd number of odd number .

so numere of ways =

                       25C0(25C1 +25C3+25C5+25C7 .........................+25C25)

                  +  25C1(25C1 +25C3+25C5+25C7 .........................+25C25)

                  +  25C2(25C1 +25C3+25C5+25C7 .........................+25C25)

                  .

                  .

                  .

                 .

                    +  25C25(25C1 +25C3+25C5+25C7 .........................+25C25)

          =  (25C0 +   25C1 +25C2+25C3+25C4 .........................+25C25)(25C1 +25C3+25C5+25C7 ........................+25C25)

          =225 .225-1

          =249

 Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin