Dear pritam
we have 25 even number and 25 odd number
for sum to be odd ,we must select odd number of odd number .
so numere of ways =
25C0(25C1 +25C3+25C5+25C7 .........................+25C25)
+ 25C1(25C1 +25C3+25C5+25C7 .........................+25C25)
+ 25C2(25C1 +25C3+25C5+25C7 .........................+25C25)
.
.
.
.
+ 25C25(25C1 +25C3+25C5+25C7 .........................+25C25)
= (25C0 + 25C1 +25C2+25C3+25C4 .........................+25C25)(25C1 +25C3+25C5+25C7 ........................+25C25)
=225 .225-1
=249
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin