ÒQ1: Why in “step response RLC series circuit” ,the inductor shows 0v after steady state has reached??

Not only in step response, in all constant sources(Doesn''t varying with time) the inductor shows 0v in steady state because

voltage across inductor  is V_L=Ldi/dt

At steady state current becomes constant.So derivative of it gives zero voltage

Answer:

                    Because inductor has been "short circuited at the position of t=0+"