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Consider the following equilibrium process at 686°C.
CO2(g) + H2(g) CO(g) + H2O(g)
The equilibrium concentrations of the reacting species are [CO] = 0.050 M, [H2] = 0.045 M, [CO2] = 0.086 M, and [H2O] = 0.040 M.


(b) If we add CO2 to increase its concentration to 0.65 mol/L, what will the concentrations of all the gases be when equilibrium is reestablished? ?M

[CO2] ?M
[H2] ? M
[CO] ? M
[H2O] ? M

Profile image of Rancho ricco
13 Years agoGrade 12
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1 Answer

Profile image of Vikas TU
ApprovedApproved Tutor Answer13 Years ago

CO2(g) + H2(g) ----------------------> CO(g) + H2O(g)
t=0 0.086 0.045 0.05 0.04
t=t 0.086 + a 0.045 + a 0.05+a 0.04+a

Now, given 
0.086 + a = 0.65
a = 0.564

[CO2] = 0.65 mol/L


[H2] = 0.609 mol/L


[CO] = 0.614 mol/L

[H2O] = 0.604 mol/L

 

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