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the EAN of nickel in k2[Ni(CN)4]

KADAMBALA VAMSI

13 Years agoGrade Upto college level

7 Answers

saisandeep Mattaparthi

Approved Tutor Answer13 Years ago

the formula= atomic no-oxidation state of central metal atom+2(no of Ligands)

=28-2+2(4)

=34

Theresh Babu Benguluri

Approved Tutor Answer13 Years ago

EAN ===== 27-2+2(4)

= 25+8

=33

KADAMBALA VAMSI

13 Years ago

mannam kiran kumar

Approved Tutor Answer13 Years ago

atomic no of metal - oxidation state of central metal + 2* no.of ligands

Ni (z=28), oxidation state +2 , no of ligands = 4

28-2+2(4) = 18 it si argan.

dipesh agrawal

Approved Tutor Answer13 Years ago

ean= z-x+y

here,

z=28

x=2

y=4*2

ean=28-2+8

=34

Ojas

7 Years ago

The sum of the number of electrons, donated by all ligands and those present on the central metal ion or atom in complex is called as effective atomic number (EAN).

• Generally EAN of central metal ion will be equal to the number of electrons in the nearest noble gas.

• If the EAN of the central metal is equal to the number of electrons in the nearest noble gas then the complex possess greater stability.

EAN = [(atomic number of central metal) – (the oxidation state of the metal) + (the number of electrons gained by the metal from the ligands through co-ordination)] = [Z metal – (ox.state of the metal) + 2(coordination number of the metal)]. Except in case of NO 3 is multiplied to coordination number of the metal.

Here:

Z metal (Ni) = 28, coordination number of the metal { n(CN) = 4},and ox.state of the metal = 2

EAN = 28 – (2) + 2(4) = 34