Dear Sidhatta,
To calculate the energy change for an atomic transition that gives rise to a radiation of 1 Hz, we will use the following relation
E = hν (1)
where h is the planck''s constant, E is the energy of the emitted radiation and ν is the frequency of this emitted radiation. We know that the energy absorbed or emitted during a transition is equal to the energy difference between the energies of the two involved energy levels.
Now h = 6.63 X 10-34 Js and ν is the frequency of the emitted radiation = 1 Hz. Substituting the values in equation (1), we get
E = 6.63 X 10-34 X 1
= 6.63 X 10-34 J
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