current electricity

Question

The total momentum of electrons in a straight wire of length, L = 1000m carrying a current, I = 70, will be (in N.s) a) 0.40 x 10-6 b) 0.20 x 10-6 c) 0.80 x 10-6 d) 0.16 x 10-6

Aman Bansal · Accepted Answer

Dear Anushka

Solution of the problem - electric current

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Discuss with colleagues and IITians> current electricity...

The total momentum of electrons in a straight wire of length, L = 1000m carrying a current, I = 70, will be (in N.s)

a) 0.40 x 10^-6

b) 0.20 x 10^-6

^c)0.80 x 10^-6

^d)0.16 x 10^-6

Anushka Prasad , 13 Years ago

Aman Bansal

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discuss with colleagues and iitians

Discuss with colleagues and IITians> current electricity...

The total momentum of electrons in a straight wire of length, L = 1000m carrying a current, I = 70, will be (in N.s) a) 0.40 x 10-6 b) 0.20 x 10-6 c) 0.80 x 10-6 d) 0.16 x 10-6

Anushka Prasad , 13 Years ago

Aman Bansal

LIVE ONLINE CLASSES

Other Related Questions on discuss with colleagues and iitians

Are core branches(Mechanical) in Top 3 NIT worth it ?

discuss with colleagues and iitians

My rank in JEE Advanced 2022 is 1871. Should I go for IIT Guwahati ECE or IIT Kanpur Mechanical and try for a branch change to CS or Electrical Engineering? Is changing your branch very difficult?

discuss with colleagues and iitians

Can i sacrifice board exams for jee mains as board exams are no where valueable as cuet and other will be seen for admission

discuss with colleagues and iitians

Is a student studying in IGCSE syllabus eligible for taking IOQP or IOQJS?

discuss with colleagues and iitians

I have wasted my 11th? Is it still possible to get into my dream iit? Do i have to cover 11 th syllabus first? When and how can i finish it?

discuss with colleagues and iitians

The total momentum of electrons in a straight wire of length, L = 1000m carrying a current, I = 70, will be (in N.s)

a) 0.40 x 10^-6

b) 0.20 x 10^-6

^c)0.80 x 10^-6

^d)0.16 x 10^-6