Harsh Bajaj
Last Activity: 12 Years ago
Hey Twinkle singh
In an equilateral triangle the median= angle bisector = altitude= perpendicular bisector
this implies that the angle between circum radius of triangle is same as half of the angle from which the radius is connected
In case of an isoscelus triangle the median= angle bisector = altitude= perpendicular bisector only for the vertex which is in between the equal sides hence angle between circum radius of triangle is same as half of the angle from which the radius is connected
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