Write a program in C++ to input 10 numbers in array and show how many are even and how many are odd?

plz reply ..i'll surely approve that...

The required program is :

========================================================

#include<iostream.h>

#include<conio.h>

void main()

{ clrscr(); 

  int a[10],i,j;

    int even=0,odd=0;

cout<<"enter the elements of the array"<<endl;

 for(i=0;i<10;++i)

{

cin>>a[i];

}

for(j=0;j<10;++j)

{  

   if (a[i]%2==0)

   even=even+1;

   else

   odd=odd+1;

}

cout<<"the number of even numbers are"<<even<<endl;

cout<<"the number of odd numbers are"<<odd<<endl;

getch();

}

=========================================================

approve the answer if helpful

#include<iostream.h>

#include<conio.h>

void main()

{

 int ar[15];

 cout<<"PLEASE INPUT THE NUMBERS:";

 for(int i=0;i<10;i++)

 {

  cin>>ar[i];

 }

int even,odd;

for(i=0;i<10;i++)

 {

  if(ar[i]%2==0)

  ++even;

  else

  ++odd;

 }

 cout<<"THE NUMBER OF EVEN NUMBERS ARE:"<<even;

 cout<<"THE NUMBER OF ODD NUMBERS ARE:"<<odd;

}

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