find sum to infinity:

1/(2^2) +1/(3^2) +1/(5^2) +1/(7^2) +...................................

please solve in detail

This can be written as 1/4 + 1/9 + 1/25 + 1/49 +..........

Here 1/4=0.25

       1/9=0.1111....

       1/25=0.04

           ....

          .....

If we add 0.25, 0.1111.... , 0.04 and so on we will get a number nearest to 1 but not 1.

Therefore approximately we will get 1 as the answer.