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what is the oxidation state of iron in brown ring complex

vivek raj , 13 Years ago
Grade 11
anser 5 Answers
Ashwin Muralidharan IIT Madras

Last Activity: 13 Years ago

Hi Vivek,

 

The OS of Fe in Brown ring is +1. The complex formed is [Fe.NO.5H2O]SO4..The charge on anion is -2. Hence charge on cationic complex has to be +2 as ring is electrically neutral. The charge on Fe on calculation comes out to be +2.. BUT electrontransfer take place from NO to Fe. Hence No and Fe acquire a charge of +1 each.
Hence the OS of Fe in brown ring is +1, due to charge transfer between Fe and NO.

 

Hope that helps.

 

All the best.

Regards,

Ashwin (IIT Madras).

Harsh jain

Last Activity: 6 Years ago

This is a fact.

A Jayanth

Last Activity: 5 Years ago

Recent researches are saying oxidation number of iron as +3.In many books it's not updated, even in ncert this thing is not updated

sree lakshmi

Last Activity: 5 Years ago

[Fe(H2O)5(NO)]SO4]  
is the formula of the complex It is known that both NO and NO+ are able to act as ligands
if we take NO as ligand the oxd state of Fe will be +2  and for NO+ it will be +1  however this question was asked in jee  and it was accepted  that Fe  is in +1 oxdn state 

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the answer to your question.
 
The OS of Fe in Brown ring is +1. The complex formed is [Fe.NO.5H2O]SO4
The charge on anion is –2. Hence charge on cationic complex has to be +2 as ring is electrically neutral.
The charge on Fe on calculation comes out to be +2.
But electrontransfer take place from NO to Fe. Hence NO and Fe acquire a charge of +1 each.
Hence the OS of Fe in brown ring is +1, due to charge transfer between Fe and NO.
 
Thanks and regards,
Kushagra

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