Ashwin Muralidharan IIT Madras
Last Activity: 13 Years ago
Hi Speed Racer,
Clearly 0≤{x}<1.
So 0≤sin{x}<sin1
Now 1<pie/2, but 1>pie/6.
So sin1<1. but sin1>1/2
So sin{x} can take all values from (0,1/2+delta]...... (where delta is >0)
And hence the range of this function would be all positive integers.
As sin{x} can be = 1/n where n=2,3,4,...... (also sin{x} = 1/2+delta, would give 1/sin{x} lies between 1 to 2)
So [1/sin{x}] = 1.
And hence range is all positive integers.
Hope that helps.
All the best.
Regards,
Ashwin (IIT Madras).