[email protected]
India's First Online IIT-JEE & NEET Coaching Platform - Trusted Since 2006
+91 87964 74404
FlagBACK
Question icon
Grade 12Discuss with colleagues and IITians

Ionic equilibria

A saturated solution of o-nitrophenol has PH=4.53. Calculate its solubility. PKa=7.23

Profile image of Krishna Deepakrao Kulkarni
17 Years agoGrade 12
Answers icon

1 Answer

Profile image of Ramesh V

Ramesh V

17 Years ago

C6H5NO3----> C6H4NO3- + H+

                                    x                       x

lets solubility be x

so PH = 4.53 or [H+] = 10-4.53  so x = 10-4.53

PKa = 7.23 or [H+] = 10-7.23

Ka = [C6H4NO3-] [H+]   

[C6H4NO3-] = Ka / [H+]
                           = 10 -7.23+4.53

                        solubility   = 2x10-3 g/L

Other Related Questions on discuss with colleagues and iitians

question mark

Are all teachers IITian? can you share their IIT and branch names?


discuss with colleagues and iitians
1 Answer Available

Last Activity: 6 Months ago

question mark
Are core branches(Mechanical) in Top 3 NIT worth it ?
discuss with colleagues and iitians
1 Answer Available

Last Activity: 4 Years ago

question mark
My rank in JEE Advanced 2022 is 1871. Should I go for IIT Guwahati ECE or IIT Kanpur Mechanical and try for a branch change to CS or Electrical Engineering? Is changing your branch very difficult?
discuss with colleagues and iitians
1 Answer Available

Last Activity: 4 Years ago

question mark
Can i sacrifice board exams for jee mains as board exams are no where valueable as cuet and other will be seen for admission 
 
discuss with colleagues and iitians
1 Answer Available

Last Activity: 4 Years ago

question mark
Is a student studying in IGCSE syllabus eligible for taking IOQP or IOQJS?
discuss with colleagues and iitians
1 Answer Available

Last Activity: 4 Years ago