vikas askiitian expertApproved Tutor Answer15 Years agoans4.9=> mod(z-1) = mod(z+1) z = x + iy so mod(x-1 + iy) = mod(x+1+iy) (x-1)2 + y2 = (x+1)2 + y2 x = 0 = y axis imaginary axis option c) is correct