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A uniform solid sphere of relative density 5 is released in water filled in a long vertical tube. Its terminal velocity acheived is V. If another uniform solid sphere of same material but double the radius is released in the same water then the terminal velocity achieved will be.
A uniform solid sphere of relative density 5 is released in water filled in a long vertical tube. Its terminal
velocity acheived is V. If another uniform solid sphere of same material but double the radius is released
in the same water then the terminal velocity achieved will be.

```
9 years ago

509 Points
```							force (F) = 6piRkV                 (V is terminal velocity)
Fi/Ff = (Ri/Rf).(Vi/Vf)   ..........1              (i , f denotes initial & final)

F = vg(p - pw)             (v is volume)
F1/F2 = v1/v2                        (v = 4/3 piR3 )
F1/F2 = (Ri/Rf)2       ...............2
equating 1 & 2
(Ri/Rf)2 = (Vi/Vf)
Vi/Vf = 1/4
Vf = 4V
approve if u like my ans
```
9 years ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions