Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A boat is moving towards east with velocity 4 m/s with respect to still water and river is flowing towards north with velocity 2 m/s and the wind is blowing towards north with velocity 6 m/s. The direction of the flag blown over by the wind hoisted on the boat is:

A boat is moving towards east with velocity 4 m/s with respect to still water and river is flowing towards north
with velocity 2 m/s and the wind is blowing towards north with velocity 6 m/s. The direction of the flag blown
over by the wind hoisted on the boat is:

Grade:12th Pass

2 Answers

melvin davis
6 Points
10 years ago

let's assume that wind doesn't affect the direction of the boat.

2194_17851_ww.GIF

now take the resultant as direction of flag makes an angle a1 with boats direction ==========

 tan a1 = (6sin(tan-1(1/2)))/(2root(5)+6cos(tan-1(1/2))

speed = root(20+36+24root(5)*cos(90-tan-1(1/2))

Sudheesh Singanamalla
114 Points
10 years ago

Velocity of boat towards east = 4 m/s

Velocity of wind and water = 2+6 = 8 m/s

 

tan θ = 4/8

θ = tan^-1(0.5)

θ = 27 degrees west north.

 

Please approve !

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free