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Length of a rectangle is increased by 50% and breadth is decreased by 25% what is the difference in the area Length of a rectangle is increased by 50% and breadth is decreased by 25% what is the difference in the area
Length of a rectangle is increased by 50% and breadth is decreased by 25% what is the difference in the area
Dear student, Let length =l breadth=b New length=1.5l new breadth=0.75b New area 1.5l*0.75b Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Dear student,
Let length =l
breadth=b
New length=1.5l
new breadth=0.75b
New area 1.5l*0.75b
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi
Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.
All the best.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
Askiitians Expert
Sagar Singh
B.Tech, IIT Delhi
let length be l and breadth be b area = l*b new length = l + l/2 = 3l /2 new breadth = b - b/4 = 3b/4 new area = 3l/2 * 3b/4 = 9 * l * b / 8 ; difference in area = 9*l*b/8 - l*b ==> (l*b) * (9/8 - 1) ==> (l*b) * 1/8 thefore difference in area = 1/8 * l*b please approve if the answer is correct
let length be l and breadth be b
area = l*b
new length = l + l/2 = 3l /2
new breadth = b - b/4 = 3b/4
new area = 3l/2 * 3b/4 = 9 * l * b / 8 ;
difference in area = 9*l*b/8 - l*b
==> (l*b) * (9/8 - 1)
==> (l*b) * 1/8
thefore difference in area = 1/8 * l*b
please approve if the answer is correct
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