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```
4. If (ω ≠ 1) be a cube root of unity and (1 + ω) 7 = l + mω, then (A) l = 0, m = 1 (B) l = 1, m = 1 (C) l = 1, m = 0 (D) l = –1, m = 1 please solve it
4.      If (ω ≠ 1) be a cube root of unity and (1 + ω)7 = l + mω, then
(A)    l = 0, m = 1
(B)    l = 1, m = 1
(C)    l = 1, m = 0
(D)    l = –1, m = 1

```
10 years ago

SAGAR SINGH - IIT DELHI
879 Points
```							Dear student,
1+w=-w^2
Therefore LHS=-w^14=-w^2=1+w=l+mw
Therefore
l=1
m=1

All the best.
Win exciting gifts by       answering the questions on Discussion Forum. So help discuss any     query   on askiitians forum and become an Elite Expert League  askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
10 years ago
509 Points
```							1+w+w2 =0          &    w3=1
(1+w)7 =  l + mw
(-w2)7 = l + mw
(-1)7 (w14) = l + mw
(-1)(w3)4 w2 = l + mw
-w2 = l + mw
1 + w = l + mw
l=1 ,m=1
hence B is correct

```
10 years ago
44 Points
```							thankx
```
10 years ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions