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```        a centrifuge consists of 4 solid cylindrical containers , each of mass m at radial distance r from the axis of rotation. time t is required to bring the centrifuge to an angular velocity W from rest under a constant torque T applied to the shaft. the radius of each container is A and the mass of the shaft and arms is small compared to m. then t=.............................
ans= 2m(a2+2r2)W/T
fig:-
```
7 years ago

419 Points
```										Dear Pranay
Plz see the pic for solution.
All the best.
AKASH GOYAL

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```
7 years ago
510 Points
```										net torque on the shaft is given...
now we can find net angular accleration of the system by
T=I(alfa)                         (T -torque,alfa - angura accleration and I is total moment of inertial of system )
alfa = T/I .........1

moment of inertial of any of cylender about the axis of rotation is I1
I1 = ma2 /2 + md2                     ( a is radius of cylender and r is perpendicular distance from axis of rotation)
I

```
7 years ago
510 Points
```										I posted the comlete solution but i dont know why remaining part is not appearing ...
here is the remaining solution remaining solution :
I1 = I (about axis of rotation) + I(abot its own axis)
I1 = mr2 + ma2 /2                          ( Icom =ma2 /2 )
total moment of inertia is 4I1
I = 4I1 = 4mr2 + 2ma2
for constant torque we can use this eq
W =W0 + (alfa)t                             (alfa is angular accleration)
t=W/alfa                         (w0  is 0 )
t = WI/T
t = 2m(a2 + 2r2 )W/T
```
7 years ago
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