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Grade 11Discuss with colleagues and IITians

: A molecule XY2 contains two σ, two π bonds and one lone pair of electrons in valence shell of X. The arrangement of lone pair as well as bond pairs is

(A) Square pyramidal (B) Linear
(C) Trigonal planar (D) Unpredictable

please explain the solution breifly

Profile image of aditya bhardwaj
15 Years agoGrade 11
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4 Answers

Profile image of piyush narang
15 Years ago

in my view it shd be a trigonal planar structure

 

Profile image of Akhilesh sharma
15 Years ago

Its structure may be as


       y- x = y

we does not consider lone pair for geometrical structure

hence structure will be as y-x

geometry should be linear

 

Profile image of zahid sharief
15 Years ago

according to me, since there are three sigma bond equivalents therefore hybridisation should be sp2(lone pair=1 sigma bond equivalent, and two sigma bonds).so structure should be trigonal planar but bond angle will be a little contracted due to lone pair and bond pair repulsions.SmileSmile

Profile image of Anoop Sunilkumar
7 Years ago
Pi bond is stay along with sigma bond ...therefore the total number of valence electron of X is equal to 8 .possible structure is Y-Xtripple bond Y..structure is linear