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: A molecule XY2 contains two σ, two π bonds and one lone pair of electrons in valence shell of X. The arrangement of lone pair as well as bond pairs is(A) Square pyramidal(B) Linear(C) Trigonal planar(D) Unpredictableplease explain the solution breifly

aditya bhardwaj , 14 Years ago
Grade 11
anser 4 Answers
piyush narang

Last Activity: 14 Years ago

in my view it shd be a trigonal planar structure

 

Akhilesh sharma

Last Activity: 14 Years ago

Its structure may be as


       y- x = y

we does not consider lone pair for geometrical structure

hence structure will be as y-x

geometry should be linear

 

zahid sharief

Last Activity: 14 Years ago

according to me, since there are three sigma bond equivalents therefore hybridisation should be sp2(lone pair=1 sigma bond equivalent, and two sigma bonds).so structure should be trigonal planar but bond angle will be a little contracted due to lone pair and bond pair repulsions.SmileSmile

Anoop Sunilkumar

Last Activity: 6 Years ago

Pi bond is stay along with sigma bond ...therefore the total number of valence electron of X is equal to 8 .possible structure is Y-Xtripple bond Y..structure is linear

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