: A molecule XY2 contains two σ, two π bonds and one lone pair of electrons in valence shell of X. The arrangement of lone pair as well as bond pairs is(A) Square pyramidal(B) Linear(C) Trigonal planar(D) Unpredictableplease explain the solution breifly
aditya bhardwaj , 14 Years ago
Grade 11
4 Answers
piyush narang
Last Activity: 14 Years ago
in my view it shd be a trigonal planar structure
Akhilesh sharma
Last Activity: 14 Years ago
Its structure may be as
y- x = y
we does not consider lone pair for geometrical structure
hence structure will be as y-x
geometry should be linear
zahid sharief
Last Activity: 14 Years ago
according to me, since there are three sigma bond equivalents therefore hybridisation should be sp2(lone pair=1 sigma bond equivalent, and two sigma bonds).so structure should be trigonal planar but bond angle will be a little contracted due to lone pair and bond pair repulsions.
Anoop Sunilkumar
Last Activity: 6 Years ago
Pi bond is stay along with sigma bond ...therefore the total number of valence electron of X is equal to 8 .possible structure is Y-Xtripple bond Y..structure is linear
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