A small rocket is launched from a height of72 feet. The height of the rocket in feet, h, isrepresented by the equationh(t) = −16t2 + 64t + 72, where t = time, inseconds. Graph this equation on theaccompanying grid. Use your graph todetermine the number of seconds that therocket will remain at or above 100 feet fromthe ground.

please check the image provided also.

When we say 100 feet from ground we should also check that the rocket is already 72 feet above the ground.

so the relative height rocket must reach to attain 100 ft from ground is actually 18 feet.

so the equation has been modified to

so now height(h) can be taken as 18 feet.

-16t^2 + 64t +72 >= 18

=> -16t^2 +64t +54 >=0

 which is reduced to  8t^2 -32t -27 >=0

for time > 5 sec this equation is positive .

SO we can say that after time= 5 sec , the rocket will be above 100 feet of height above ground.

PS: there might be some printing error in equation as it is giving only one valid value of time.

Approved

Sir, you have taken the relative height as 18 feet I think you are incorrect because it must be 28 feet