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the 50 KG homogeneous smooth sphere rests on the 30 degree incline A and against the smooth vertical wall B.calculate contact forces at A and B.
let the contact force acting on point A be A newtons and acting on point B be B newtons.then by resolving forces along horizontal and vertical directions
A cos 30=mg
A sin 30=B
A=50*9.8/.866=565.81 Newton
B=565.81*.5=282.90 Newton
sorry sir,but diagram is not clear.pls post again
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