the 50 KG homogeneous smooth sphere rests on the 30 degree incline A and against the smooth vertical wall B.calculate contact forces at A and B.

let the contact force acting on point A be A newtons and acting on point B be B newtons.then by resolving forces along horizontal and vertical directions

A cos 30=mg

A sin 30=B

A=50*9.8/.866=565.81 Newton

B=565.81*.5=282.90 Newton

sorry sir,but diagram is not clear.pls post again