16ml of a gaseous compound CnH3nOm was mixed with

Question

16ml of a gaseous compound CnH3nOm was mixed with 60ml O2 and exploded . The gas mixture on cooling occupies 44ml . After treatement with KOH solution,the volume of gas remaining was 12ml .Deduce the formula of compound.

Arun · Accepted Answer

C n​H 3n​O m​+[n+ 43n​− 2m​]O 2​→nCO 2​+ 23n​H 2​OVolume before reaction 16 60 0 0Volume after reaction 0 60−16[n+ 43n​− 2m​] 16n 24nVolume of gases left = 60−16[ 47n​−d 2m​]+16n44=60−12n+8m12n−8m=16 ...(i)Volume of O 2​left = 60−16[ 47n​− 2m​]12=60−28n+8m28n−8m=48 ...(ii)By equations (i) and (ii) , n=2,m=1Therefore, the gas is C 2​H 6​O

Discuss with colleagues and IITians> 16ml of a gaseous compound CnH3nOm was mi...

16ml of a gaseous compound CnH3nOm was mixed with 60ml O2 and exploded . The gas mixture on cooling occupies 44ml . After treatement with KOH solution,the volume of gas remaining was 12ml .Deduce the formula of compound.

aman jha , 10 Years ago

Arun

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Discuss with colleagues and IITians> 16ml of a gaseous compound CnH3nOm was mi...

16ml of a gaseous compound CnH3nOm was mixed with 60ml O2 and exploded . The gas mixture on cooling occupies 44ml . After treatement with KOH solution,the volume of gas remaining was 12ml .Deduce the formula of compound.

aman jha , 10 Years ago

Arun

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Are core branches(Mechanical) in Top 3 NIT worth it ?

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