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Grade 12th passDiscuss with colleagues and IITians

please give me the solution for this question with steps.....

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ragulvarma

9 Years agoGrade 12th pass

1 Answer

Arun

6 Years ago

Output = 20 h.p = 14.914 Kw

input = 400 Kcal/min = 27.8932

Higher temperature ( T ) = 227° C = 273 + 227 = 500°C

Lower temperature ( t ) = 27° C = 273 + 27 = 300°C

Ideal coeffiecient of performance = = 0.4

Actual cop = output /input = 14.914/27.8932 = 0.532

Here the actual cop is greater than ideal which is not possible.

Therefore his claim is false

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